Guess Your Birthday!
Here's a fun trick to show a friend, a group, or an entire class of people. I have used this fun mathematical trick on thousands of people since 1963 when I learned it. Tell the person (or class) to think of their birthday...and that you are going to guess it.Step 1) Have them take the month number from their birthday: January = 1, Feb = 2 etc.
Step 2) Multiply that by 5
Step 3) Then add 6
Step 4) Then multiply that total by 4
Step 5) Then add 9
Step 6) Then multiply this total by 5 once again
Step 7) Finally, have them add to that total the day they were born on. If they were born on the 18th, they add 18, etc.
Step 2) Multiply that by 5
Step 3) Then add 6
Step 4) Then multiply that total by 4
Step 5) Then add 9
Step 6) Then multiply this total by 5 once again
Step 7) Finally, have them add to that total the day they were born on. If they were born on the 18th, they add 18, etc.
Have them give you the total. In your head, subtract 165, and you will have the month and day they were born on!
How It Works: Let M be the month number and D will be the day number. After the seven steps the expression for their calculation is:
5 (4 (5 M + 6 ) + 9 ) + D = 100 M + D + 165
Thus, if you subtract off the 165, what will remain will be the month in hundreds plus the day!
By the way, if you wish to know how many minutes and seconds you have been alive and lots more about when you were born, you might like to try this website ==> Birthday Calculator
Divisibility Rules!
To find if some number X is divisible by a certain number, test the number by using the information in the table below.
By 2 | If the last digit divisible by two, then X is too |
By 3 | If the sum of the digits of the number X is divisible by three, then X is too |
By 4 | If the last two digits are divisible by four, then X is too |
By 5 | If the last digit is 5 or 0, then X is divisible by 5 |
By 6 | If X is divisible by 2 and by 3, then X is divisible by 6 |
By 7 | This rule is called L-2M. What you do is to double the last digit of the number X and subtract it from X without its last digit. For instance, if the number X you are testing is345678, you would subtract 16 from 34567. Repeat this procedure until you get a number that you know for sure is or is not divisible by seven. Then the X's divisibility will be the same. |
By 8 | If the last three digits are divisible by 8, then X is too |
By 9 | If the sum of the digits of the number X is divisible by nine, then X is too |
By 10 | If the last digit of X is 0, then X is divisible by 10 |
By 11 | What you do here is to make two sums of digits and subtract them. The first sum is the sum of the first, third, fifth, seventh, etc. digits and the other sum is the sum of the second, fourth, sixth, eighth, etc. digits. If, when you subtract the sums from each other, the difference is divisible by 11, then the number X is too |
By 12 | If X is divisible by 4 and by 3, then X is divisible by 12 |
By 13 | This rule is called L+4M. What you do is to quadruple the last digit of the number X and add it from X without its last digit. For instance, if the number X you are testing is345678, you would add 32 to 34567. Repeat this procedure until you get a number that you know for sure is or is not divisible by thirteen. Then the X's divisibility will be the same. |
By 14 | If X is divisible by 7 and by 2, then X is divisible by 14 |
By 15 | If X is divisible by 5 and by 3, then X is divisible by 15 |
By 16 | If the last four digits are divisible by 16, then X is too |
By 17* | This rule is called L-5M. See rules for 7 and 13 on how to apply. |
By 18 | If X is divisible by 9 and by 2, then X is divisible by 18 |
By 19* | This rule is called L+2M. See rules for 7 and 13 on how to apply. |
By 20 | If X is divisible by 5 and by 4, then X is divisible by 20 |
By 21 | If X is divisible by 7 and by 3, then X is divisible by 21 |
By 22 | If X is divisible by 11 and by 2, then X is divisible by 22 |
By 24 | If X is divisible by 8 and by 3, then X is divisible by 24 |
By 25 | If the last two digits of X are divisible by 25, then X is too |
Higher | You can use multiple rules for multiple divisors...for instance, to check if a number is divisible by 57, check to see if it is divisible by 19 and 3, etc., since 57 = 19 x 3... |
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